Optimal. Leaf size=650 \[ \frac {\sqrt {a+b} \tan ^{-1}\left (\frac {\sqrt {a+b} \tan (c+d x)}{\sqrt {a+b \tan ^4(c+d x)}}\right )}{2 d}+\frac {\sqrt {b} \tan (c+d x) \sqrt {a+b \tan ^4(c+d x)}}{d \left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right )}-\frac {\sqrt [4]{b} (a+b) \left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right ) \sqrt {\frac {a+b \tan ^4(c+d x)}{\left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \tan (c+d x)}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{2 \sqrt [4]{a} d \left (\sqrt {a}-\sqrt {b}\right ) \sqrt {a+b \tan ^4(c+d x)}}+\frac {\sqrt [4]{b} \left (\sqrt {a}-\sqrt {b}\right ) \left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right ) \sqrt {\frac {a+b \tan ^4(c+d x)}{\left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \tan (c+d x)}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{2 \sqrt [4]{a} d \sqrt {a+b \tan ^4(c+d x)}}-\frac {\sqrt [4]{a} \sqrt [4]{b} \left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right ) \sqrt {\frac {a+b \tan ^4(c+d x)}{\left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \tan (c+d x)}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{d \sqrt {a+b \tan ^4(c+d x)}}+\frac {\left (\sqrt {a}+\sqrt {b}\right ) (a+b) \left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right ) \sqrt {\frac {a+b \tan ^4(c+d x)}{\left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right )^2}} \Pi \left (-\frac {\left (\sqrt {a}-\sqrt {b}\right )^2}{4 \sqrt {a} \sqrt {b}};2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \tan (c+d x)}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{4 \sqrt [4]{a} \sqrt [4]{b} d \left (\sqrt {a}-\sqrt {b}\right ) \sqrt {a+b \tan ^4(c+d x)}} \]
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Rubi [A] time = 0.56, antiderivative size = 650, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.438, Rules used = {3661, 1209, 1198, 220, 1196, 1217, 1707} \[ \frac {\sqrt {a+b} \tan ^{-1}\left (\frac {\sqrt {a+b} \tan (c+d x)}{\sqrt {a+b \tan ^4(c+d x)}}\right )}{2 d}+\frac {\sqrt {b} \tan (c+d x) \sqrt {a+b \tan ^4(c+d x)}}{d \left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right )}-\frac {\sqrt [4]{b} (a+b) \left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right ) \sqrt {\frac {a+b \tan ^4(c+d x)}{\left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \tan (c+d x)}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{2 \sqrt [4]{a} d \left (\sqrt {a}-\sqrt {b}\right ) \sqrt {a+b \tan ^4(c+d x)}}+\frac {\sqrt [4]{b} \left (\sqrt {a}-\sqrt {b}\right ) \left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right ) \sqrt {\frac {a+b \tan ^4(c+d x)}{\left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \tan (c+d x)}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{2 \sqrt [4]{a} d \sqrt {a+b \tan ^4(c+d x)}}-\frac {\sqrt [4]{a} \sqrt [4]{b} \left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right ) \sqrt {\frac {a+b \tan ^4(c+d x)}{\left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \tan (c+d x)}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{d \sqrt {a+b \tan ^4(c+d x)}}+\frac {\left (\sqrt {a}+\sqrt {b}\right ) (a+b) \left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right ) \sqrt {\frac {a+b \tan ^4(c+d x)}{\left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right )^2}} \Pi \left (-\frac {\left (\sqrt {a}-\sqrt {b}\right )^2}{4 \sqrt {a} \sqrt {b}};2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \tan (c+d x)}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{4 \sqrt [4]{a} \sqrt [4]{b} d \left (\sqrt {a}-\sqrt {b}\right ) \sqrt {a+b \tan ^4(c+d x)}} \]
Antiderivative was successfully verified.
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Rule 220
Rule 1196
Rule 1198
Rule 1209
Rule 1217
Rule 1707
Rule 3661
Rubi steps
\begin {align*} \int \sqrt {a+b \tan ^4(c+d x)} \, dx &=\frac {\operatorname {Subst}\left (\int \frac {\sqrt {a+b x^4}}{1+x^2} \, dx,x,\tan (c+d x)\right )}{d}\\ &=-\frac {\operatorname {Subst}\left (\int \frac {b-b x^2}{\sqrt {a+b x^4}} \, dx,x,\tan (c+d x)\right )}{d}+\frac {(a+b) \operatorname {Subst}\left (\int \frac {1}{\left (1+x^2\right ) \sqrt {a+b x^4}} \, dx,x,\tan (c+d x)\right )}{d}\\ &=-\frac {\left (\sqrt {a} \sqrt {b}\right ) \operatorname {Subst}\left (\int \frac {1-\frac {\sqrt {b} x^2}{\sqrt {a}}}{\sqrt {a+b x^4}} \, dx,x,\tan (c+d x)\right )}{d}+\frac {\left (\left (\sqrt {a}-\sqrt {b}\right ) \sqrt {b}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {a+b x^4}} \, dx,x,\tan (c+d x)\right )}{d}+\frac {\left (\sqrt {a} (a+b)\right ) \operatorname {Subst}\left (\int \frac {1+\frac {\sqrt {b} x^2}{\sqrt {a}}}{\left (1+x^2\right ) \sqrt {a+b x^4}} \, dx,x,\tan (c+d x)\right )}{\left (\sqrt {a}-\sqrt {b}\right ) d}-\frac {\left (\sqrt {b} (a+b)\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {a+b x^4}} \, dx,x,\tan (c+d x)\right )}{\left (\sqrt {a}-\sqrt {b}\right ) d}\\ &=\frac {\sqrt {a+b} \tan ^{-1}\left (\frac {\sqrt {a+b} \tan (c+d x)}{\sqrt {a+b \tan ^4(c+d x)}}\right )}{2 d}+\frac {\sqrt {b} \tan (c+d x) \sqrt {a+b \tan ^4(c+d x)}}{d \left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right )}-\frac {\sqrt [4]{a} \sqrt [4]{b} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \tan (c+d x)}{\sqrt [4]{a}}\right )|\frac {1}{2}\right ) \left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right ) \sqrt {\frac {a+b \tan ^4(c+d x)}{\left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right )^2}}}{d \sqrt {a+b \tan ^4(c+d x)}}+\frac {\left (\sqrt {a}-\sqrt {b}\right ) \sqrt [4]{b} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \tan (c+d x)}{\sqrt [4]{a}}\right )|\frac {1}{2}\right ) \left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right ) \sqrt {\frac {a+b \tan ^4(c+d x)}{\left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right )^2}}}{2 \sqrt [4]{a} d \sqrt {a+b \tan ^4(c+d x)}}-\frac {\sqrt [4]{b} (a+b) F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \tan (c+d x)}{\sqrt [4]{a}}\right )|\frac {1}{2}\right ) \left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right ) \sqrt {\frac {a+b \tan ^4(c+d x)}{\left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right )^2}}}{2 \sqrt [4]{a} \left (\sqrt {a}-\sqrt {b}\right ) d \sqrt {a+b \tan ^4(c+d x)}}+\frac {\left (\sqrt {a}+\sqrt {b}\right ) (a+b) \Pi \left (-\frac {\left (\sqrt {a}-\sqrt {b}\right )^2}{4 \sqrt {a} \sqrt {b}};2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \tan (c+d x)}{\sqrt [4]{a}}\right )|\frac {1}{2}\right ) \left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right ) \sqrt {\frac {a+b \tan ^4(c+d x)}{\left (\sqrt {a}+\sqrt {b} \tan ^2(c+d x)\right )^2}}}{4 \sqrt [4]{a} \left (\sqrt {a}-\sqrt {b}\right ) \sqrt [4]{b} d \sqrt {a+b \tan ^4(c+d x)}}\\ \end {align*}
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Mathematica [C] time = 0.81, size = 219, normalized size = 0.34 \[ \frac {\sqrt {\frac {b \tan ^4(c+d x)}{a}+1} \left (\sqrt {a} \sqrt {b} E\left (\left .i \sinh ^{-1}\left (\sqrt {\frac {i \sqrt {b}}{\sqrt {a}}} \tan (c+d x)\right )\right |-1\right )+\left (\sqrt {a}-i \sqrt {b}\right ) \left (\left (\sqrt {b}-i \sqrt {a}\right ) \Pi \left (-\frac {i \sqrt {a}}{\sqrt {b}};\left .i \sinh ^{-1}\left (\sqrt {\frac {i \sqrt {b}}{\sqrt {a}}} \tan (c+d x)\right )\right |-1\right )-\sqrt {b} F\left (\left .i \sinh ^{-1}\left (\sqrt {\frac {i \sqrt {b}}{\sqrt {a}}} \tan (c+d x)\right )\right |-1\right )\right )\right )}{d \sqrt {\frac {i \sqrt {b}}{\sqrt {a}}} \sqrt {a+b \tan ^4(c+d x)}} \]
Antiderivative was successfully verified.
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fricas [F] time = 1.15, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\sqrt {b \tan \left (d x + c\right )^{4} + a}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \sqrt {b \tan \left (d x + c\right )^{4} + a}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 0.57, size = 531, normalized size = 0.82 \[ \frac {-\frac {b \sqrt {1-\frac {i \sqrt {b}\, \left (\tan ^{2}\left (d x +c \right )\right )}{\sqrt {a}}}\, \sqrt {1+\frac {i \sqrt {b}\, \left (\tan ^{2}\left (d x +c \right )\right )}{\sqrt {a}}}\, \EllipticF \left (\tan \left (d x +c \right ) \sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}, i\right )}{\sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}\, \sqrt {a +b \left (\tan ^{4}\left (d x +c \right )\right )}}+\frac {i \sqrt {b}\, \sqrt {a}\, \sqrt {1-\frac {i \sqrt {b}\, \left (\tan ^{2}\left (d x +c \right )\right )}{\sqrt {a}}}\, \sqrt {1+\frac {i \sqrt {b}\, \left (\tan ^{2}\left (d x +c \right )\right )}{\sqrt {a}}}\, \EllipticF \left (\tan \left (d x +c \right ) \sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}, i\right )}{\sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}\, \sqrt {a +b \left (\tan ^{4}\left (d x +c \right )\right )}}-\frac {i \sqrt {b}\, \sqrt {a}\, \sqrt {1-\frac {i \sqrt {b}\, \left (\tan ^{2}\left (d x +c \right )\right )}{\sqrt {a}}}\, \sqrt {1+\frac {i \sqrt {b}\, \left (\tan ^{2}\left (d x +c \right )\right )}{\sqrt {a}}}\, \EllipticE \left (\tan \left (d x +c \right ) \sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}, i\right )}{\sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}\, \sqrt {a +b \left (\tan ^{4}\left (d x +c \right )\right )}}+\frac {a \sqrt {1-\frac {i \sqrt {b}\, \left (\tan ^{2}\left (d x +c \right )\right )}{\sqrt {a}}}\, \sqrt {1+\frac {i \sqrt {b}\, \left (\tan ^{2}\left (d x +c \right )\right )}{\sqrt {a}}}\, \EllipticPi \left (\tan \left (d x +c \right ) \sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}, \frac {i \sqrt {a}}{\sqrt {b}}, \frac {\sqrt {-\frac {i \sqrt {b}}{\sqrt {a}}}}{\sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}}\right )}{\sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}\, \sqrt {a +b \left (\tan ^{4}\left (d x +c \right )\right )}}+\frac {b \sqrt {1-\frac {i \sqrt {b}\, \left (\tan ^{2}\left (d x +c \right )\right )}{\sqrt {a}}}\, \sqrt {1+\frac {i \sqrt {b}\, \left (\tan ^{2}\left (d x +c \right )\right )}{\sqrt {a}}}\, \EllipticPi \left (\tan \left (d x +c \right ) \sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}, \frac {i \sqrt {a}}{\sqrt {b}}, \frac {\sqrt {-\frac {i \sqrt {b}}{\sqrt {a}}}}{\sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}}\right )}{\sqrt {\frac {i \sqrt {b}}{\sqrt {a}}}\, \sqrt {a +b \left (\tan ^{4}\left (d x +c \right )\right )}}}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \sqrt {b \tan \left (d x + c\right )^{4} + a}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \sqrt {b\,{\mathrm {tan}\left (c+d\,x\right )}^4+a} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \sqrt {a + b \tan ^{4}{\left (c + d x \right )}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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